Alfred Ajibola
- 01st February, 2026 @ 09:27 PM
Topics in Mathematics
Linear Equation in Mathematics Word Problems leading to Algebraic Expression BODMAS in Algebra Multiplication and Division in Algebra Addition and Subtraction in Algebra Multiplication of Number Bases Subtraction of Number Bases Addition of Number Bases Division of Number Base Number Base Conversion Number Base System Significant Figures Rounding Off Numbers Decimal Place Value Fraction Word Problems Word Problems in Fraction Multiplication and Division of Fractions Addition and Subtraction of Fractions Expressing One Quantity as a Percentage of Another Expressing One Quantity as a Fraction of AnotherAcademic Questions in Mathematics

What type of polygon is shown in the above image?
A. Nonagon
B. Decagon
C. Octagon
D. Hexagon
E. Hepagon
F. Pentagon
Which of the following is not part of a circle?
A. Section
B. Sector
C. Segment
D. Semicircle
E. Secant
F. Center

What angle is shown in the above image?
A. Complementary
B. Supplementary
C. Acute
D. Obtuse
E. Reflex
F. Straight
An angle greater than 90o but less than 180o is termed _____.
A. Complementary
B. Supplementary
C. Acute
D. Obtuse
E. Reflex
F. Straight
Factorize 12a2 - 20a + 3
A. (6a - 1)(2a - 3)
B. (6a - 1)(2a + 3)
C. (6a + 1)(2a - 3)
D. (6a + 1)(2a + 3)
E. (-6a + 1)(2a - 3)
F. (-6a + 1)(2a + 3)
Simplify 10ab + 7ab
A. 17ab2
B. 17a2b2
C. 3ab2
D. 3a2b2
E. 17ab
F 3ab
Which of the following is not a type of angle?
A. Right angle
B. Left Angle
C. Acute Angle
D. Complete Angle
E. Straight Angle
F. Reflex angle
Two lines that can never meet each other are best considered as _____ lines.
The addition of numbers in different bases is quite straightforward. It follows a similar procedure as in the addition of base 10. The principle of addition of number base is stated below:
In number base addition, when an addition in a column equals or exceeds the base number, we'll divide the sum by the base; writing down the remainder, and carrying the whole number quotient to the next column.
This above principle is shown in binary or base 2 addition:
0 + 0 = 0
0 + 1 = 1
1 + 1= 2/2 (Carry 1 and write down remainder 0)
1 + 1 + 1 = 3/2 (Carry 1 and write down remainder 1)
Note: This same principle applies to other bases. That is: "when an addition in a column equals or exceeds the base number, we'll divide the sum by the base, while writing down the remainder, and carrying the whole number quotient to the next column".
Please read on base 2 system (binary) here.
It is noteworthy to state that number base addition can easily be carried out through base 10 conversion. The steps below are followed using this method:
Step 1: Convert the bases to be added into base 10.
Step 2: Add the base 10 numbers (derived from step 1).
Step 3: Convert the base 10 addition result (in step 2) to the required base in the question.
Please read on number base conversion here.
You can read on the division of number bases here.
Example 1
Solution
Align the two binary numbers by their place values. This is shown below:
Step 1: Add the rightmost digits.
0 + 1= 1
Step 2: Add the leftmost digits We add the leftmost digits:
1 + 1 = 2/2 (Carry 1 and write down remainder 0)
Step 3: 1 carried = 1
Solution Through Base 10 Conversion
Step 1: Convert 102 to base 10
(1 × 21) + (0 × 20)
2 + 0 = 210
Step 2: Convert 112 to base 10
(1 × 21) + (1 × 20)
2 + 1 = 310
Step 3: Add both base 10 results
2 + 3 = 510
Step 4: Covert the base 10 result to base 2
5 ÷ 2 = 2 R 1
2 ÷ 2 = 1 R 0
0 ÷ 2 = 0 R 1
Read remainder from bottom to top.
Example 2
Solution
Align the two base numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:
Step 1: Perform base addition with carries. Add the digits from right to left, following the base addition rule.
1 + 1 = 2/2 (Carry 1 and write down remainder 0)
Step 2: Second rightmost column
1 carried + 1 + 0 = 2/2 (Carry 1 and write down remainder 0)
Step 3: Third rightmost column
1 carried + 0 + 1 = 2/2 (Carry 1 and write down remainder 0)
Step 4: Fourth rightmost column
1 carried + 1 + 1 = 3/2 (Carry 1 and write down remainder 1)
Step 5: Left column
1 carried + 1 + 0 = 2/2 (Carry 1 and write down remainder 0)
Step 6: 1 + 0 = 1
Solution Through Base 10 Conversion
Step 1: Convert 110112 to base 10
(1 × 24) + (1 × 23) + (0 × 22) + (1 × 21) + (1 × 20)
16 + 8 + 0 + 2 + 1 = 2710
Step 2: Convert 11012 to base 10
(1 × 23) + (1 × 22) + (0 × 21) + (1 × 20)
8 + 4 + 0 + 1 = 1310
Step 3: Subtract both base 10 results
27 + 13 = 4010
Step 4: Covert the base 10 result to base 2
40 ÷ 2 = 20 R 0
20 ÷ 2 = 10 R 0
10 ÷ 2 = 5 R 0
5 ÷ 2 = 2 R 1
2 ÷ 2 = 1 R 0
1 ÷ 2 = 0 R 1
Read remainder from bottom to top.
Example 3
Solution
Align the two base 4 numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:
Step 1: Perform base 4 addition with carries. Add the digits from right to left, following the base addition rule.
3 + 2 = 5/4 (Carry 1 and write down remainder 1)
Step 2: Second rightmost column
1 carried + 3 + 1 = 5/4 (Carry 1 and write down remainder 1)
Step 3: Third rightmost column
1 carried + 0 + 0 = 1
Step 4: Fourth rightmost column
2 + 0 = 2
Step 5: Left column
0 + 3 = 3
Solution Through Base 10 Conversion
Step 1: Convert 20334 to base 10
(2 × 43) + (0 × 42) + (3 × 41) + (3 × 40)
128 + 0 + 12 + 3 = 14310
Step 2: Convert 300124 to base 10
(3 × 44) + (0 × 43) + (0 × 42) + (1 × 41) + (2 × 40)
768 + 0 + 0 + 4 + 2 = 77410
Step 3: Add both base 10 results
143 + 774 = 91710
Step 4: Covert the base 10 result to base 5
917 ÷ 4 = 229 R 1
229 ÷ 4 = 57 R 1
57 ÷ 4 = 14 R 1
14 ÷ 4 = 3 R 2
3 ÷ 4 = 0 R 3
Read remainder from bottom to top.
Example 4
Solution
Align the two base 6 numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:
Step 1: Perform base 6 addition with carries. Add the digits from right to left, following the base addition rule.
5 + 2 = 7/6 (Carry 1 and write down remainder 1)
Step 2: Second rightmost column
1 carried + 4 + 3 = 8/6 (Carry 1 and write down remainder 2)
Step 3: Third rightmost column
1 carried + 4 + 3 = 8/6 (Carry 1 and write down remainder 2)
Step 4: Fourth rightmost column
1 carried + 0 + 0 = 1
Step 5: Left column
5 + 0 = 5
Solution Through Base 10 Conversion
Step 1: Convert 504426 to base 10
(5 × 64) + (0 × 63) + (4 × 62) + (4 × 61) + (2 × 60)
6480 + 0 + 144 + 24 + 2 = 665010
Step 2: Convert 3356 to base 10
(3 × 62) + (3 × 61) + (5 × 60)
108 + 18 + 5 = 13110
Step 3: Add both base 10 results
6650 + 131 = 678110
Step 4: Covert the base 10 result to base 5
6781 ÷ 6 = 1130 R 1
1130 ÷ 6 = 188 R 2
188 ÷ 6 = 31 R 2
31 ÷ 6 = 5 R 1
5 ÷ 6 = 0 R 5
Read remainder from bottom to top.
Example 5
Solution
Align the base numbers Align the two binary numbers by their place values.
Step 1: Perform binary addition with carries. Add the digits from right to left, following base addition rules:
1 + 1 = 2/2 (Carry 1 and write down remainder 0)
Step 2: Second rightmost column
1 carried + 0 + 1 = 2/2 (Carry 1 and write down remainder 0)
Step 3: Left column
1 carried + 1 + 1 = 3/2 (Carry 1 and write down remainder 1)
Step 4: 1 carried = 1
Answer: Combine the direct answers and remainders = 11002
Solution Through Base 10 Conversion
Step 1: Convert 430025 to base 10
(1 × 22) + (0 × 21) + (1 × 20)
4 + 0 + 1 = 510
Step 2: Convert 1112 to base 10
(1 × 22) + (1 × 21) + (1 × 20)
4 + 2 + 1 = 710
Step 3: Add both base 10 results
5 + 7 = 1210
Step 4: Covert the base 10 result to base 5
12 ÷ 2 = 6 R 0
6 ÷ 2 = 3 R 0
3 ÷ 2 = 1 R 1
1 ÷ 2 = 0 R 1
Read remainder from bottom to top.
Example 6
Solution
Align the two base 5 numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:
Step 1: Perform base 5 addition with carries. Add the digits from right to left, following the base addition rule.
2 + 1 = 3
Step 2: Second rightmost column
3 + 2 = 5/5 (Carry 1 and write down remainder 0)
Step 3: Third rightmost column
1 carried + 4 + 3 = 8/5 (Carry 1 and write down remainder 3)
Step 4: Fourth rightmost column
1 carried + 0 + 4 = 5/5 (Carry 1 and write down remainder 0)
Step 5: Left column
1 carried + 1 + 0 = 2
Solution Through Base 10 Conversion
Step 1: Convert 104325 to base 10
(1 × 54) + (0 × 53) + (4 × 52) + (3 × 51) + (2 × 50)
625 + 0 + 100 + 15 + 2 = 74210
Step 2: Convert 43215 to base 10
(4 × 53) + (3 × 52) + (2 × 51) + (1 × 50)
500 + 75 + 10 + 1 = 58610
Step 3: Add both base 10 results
742 + 586 = 132810
Step 4: Covert the base 10 result to base 5
1328 ÷ 5 = 265 R 3
283 ÷ 5 = 53 R 0
53 ÷ 5 = 10 R 3
10 ÷ 5 = 2 R 0
2 ÷ 5 = 0 R 2
Read remainder from bottom to top.
Example 7
Solution
Align the two base 3 numbers by their place values. This is shown below:
Step 1: Perform base 3 addition with carries. Add the digits from right to left, following the base addition rule.
2 + 1 = 3/3 (Carry 1 and write down remainder 0)
Step 2: Second rightmost column
1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)
Step 3: Third rightmost column
1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)
Step 4: Fourth rightmost column
1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)
Step 5: Left column
1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)
Step 6: 1 carried = 1
Solution Through Base 10 Conversion
Step 1: Convert 222223 to base 10
(2 × 34) + (2 × 33) + (2 × 32) + (2 × 31) + (2 × 30)
162 + 54 + 18 + 6 + 2 = 24210
Step 2: Convert 111113 to base 10
(1 × 34) + (1 × 33) + (1 × 32) + (1 × 31) + (1 × 30)
81 + 27 + 9 + 3 + 1 = 12110
Step 3: Add both base 10 results
242 + 121 = 36310
Step 4: Covert the base 10 result to base 5
363 ÷ 3 = 121 R 0
121 ÷ 3 = 40 R 1
40 ÷ 3 = 13 R 1
13 ÷ 3 = 4 R 1
4 ÷ 3 = 1 R 1
1 ÷ 3 = 0 R 1
Read remainder from bottom to top.
Example 8
Solution
Align the two binary numbers by their place values. This is shown below:
Step 1: Perform binary addition with carries. Add the digits from right to left, following the base addition rule:
0 + 1 = 1
Step 2: Second rightmost column
1 + 0 = 1
Step 3: Third rightmost column
1 + 0 = 1
Step 4: Left column
1 + 1 = 2/2 (Carry 1 and write down remainder 0)
Step 5: 1 carried = 1
Solution Through Base 10 Conversion
Step 1: Convert 11102 to base 10
(1 × 23) + (1 × 22) + (1 × 21) + (0 × 20)
8 + 4 + 2 + 0 = 1410
Step 2: Convert 10012 to base 10
(1 × 23) + (0 × 22) + (0 × 21) + (1 × 20)
8 + 0 + 0 + 1 = 910
Step 3: Add both base 10 results
14 + 9 = 2310
Step 4: Covert the base 10 result to base 5
23 ÷ 2 = 11 R 1
11 ÷ 2 = 5 R 1
5 ÷ 2 = 2 R 1
2 ÷ 2 = 1 R 0
1 ÷ 2 = 0 R 1
Read remainder from bottom to top.
Example 9
1001002 + 112
Solution
Align the two binary numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:
Step 1: Perform binary addition with carries. Add the digits from right to left, following the base addition rules
0 + 1 = 1
Step 2: Second rightmost column
0 + 1 = 1
Step 3: Third rightmost column
1 + 0 = 1
Step 4: Fourth rightmost column
0 + 0 = 0
Step 5: Fifth rightmost column
0 + 0 = 0
Step 6: Left column
1 + 0 = 1
Answer: Combine the direct answers and remainders = 1001112
Solution Through Base 10 Conversion
Step 1: Convert 1001002 to base 10
(1 × 25) + (0 × 24) + (0 × 23) + (1 × 22) + (0 × 21) + (0 × 20)
32 + 0 + 0 + 4 + 0 + 0 = 3610
Step 2: Convert 112 to base 10
(1 × 21) + (1 × 20)
2 + 1 = 310
Step 3: Add both base 10 results
36 + 3 = 3910
Step 4: Covert the base 10 result to base 5
39 ÷ 2 = 19 R 1
19 ÷ 2 = 9 R 1
9 ÷ 2 = 4 R 1
4 ÷ 2 = 2 R 0
2 ÷ 2 = 1 R 0
1 ÷ 2 = 0 R 1
Read remainder from bottom to top.
Please read on subtraction of number bases here.
Please read on multiplication and division in algebra here.
Please read on the use of BODMAS in mathematics here.
Add the following bases:
3214 + 2134
42315 + 12345
38719 + 38879
101101112 +.1101112
7000018 +.1666678
6543217 + 1234567
432115 + 221435
644437 + 163347
78764910 + 9918110
881239 + 235689
Please read on word problems leading to algebraic expressions here.
Please read on mathematics week 9 topic for jss1 first term here.
Please read on mathematics scheme of work for jss1 first term here.
Kindly share this article via the links below:
![]()
Please click here to contact Alfred if you require any of the following services:
If you need a standard website at an affordable price.
Online training on the academic subjects: biology, chemistry and basic science.
If you require an advanced smart school management system (web application) for your school.
Click here to read on Len Academy Smart School Software.
Please click here to follow Len Academy on Google News.
Amazing facts in Mathematics
The opposite sides of a dice will always give a sum of seven
31,556,926 seconds makes one year
From 0 through 1000, the only number that has the letter 'a' in it is 'one thousand'
÷
The division symbol '÷' is actually called an obelus
Four is the only number in the English language that is spelt with the same number of letters as the number (4) itself
40 is spelt as forty and not 'fourty'. It is the only number that is spelt with letters arranged in alphabetical order
An odd number is a number that cannot be divisible by 2.
Every odd number has an 'e' in its spelling. They include:
555 in Thailand sounds like 'hahaha'. This is because the number '5' means 'ha' in Thailand
In mathematics, 10! means 10 factorial. Below is its calculation:
10! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 3628800
Interestingly, 3628800 seconds is the same as 42 days
42 days is the same as 6 weeks
We can therefore say that 10! equals 6 weeks or 3628800 seconds in mathematics
When you multiply 111,111,111 by 111,111,111; the result equals 12,345,678,987,654,321
Notable points in Mathematics
Let's use algebra to explain the simple statement below:
I am a number. When you subtract 3 from me, the result is 9. what number am I ?
Of course we know the answer is 12. You probably guessed it from your mind because it was that simple. The truth is, We could have a much more complicated statement of such; and that is where algebra comes into play.
Now, to apply algebra in the above statement, we use letters or alphabets to represent the unknown number(s). So using algebra, we can write:
Let the number be y
y - 3 = 9
y = 9 + 3
y = 12

The image above shows a right angled triangle. The angle of the above right triangle is denoted as θ. Below are some points to note:
Hypotenuse is always the longest side of the triangle.
Opposite is the side opposite the angle (θ)
Adjacent is the shorter side next to the angle (θ)
Each of Sin θ, cos θ and tan θ are the ratio of sides of the right triangle. They are calculated by using the formula (margic word) sohcahtoa:

soh
Sin θ = Opposite/Hypotenuse
cah
Cos θ = Adjacent/Hypotenuse
toa
Tan θ = Opposite/Adjacent

Circumference in mathematics means the distance around the edge of a circle (or a another curved surface).
Circumference is to circle or any other curved surface

Perimeter means the distance around a square or rectangle or polygon.
Perimeter is to square or rectangle or polygon