Mathematics | Class: JSS1 | Term: 1st

Addition of Number Bases

len Alfred Ajibola - 01st February, 2026 @ 09:27 PM

Topics in Mathematics

Linear Equation in Mathematics Word Problems leading to Algebraic Expression BODMAS in Algebra Multiplication and Division in Algebra Addition and Subtraction in Algebra Multiplication of Number Bases Subtraction of Number Bases Addition of Number Bases Division of Number Base Number Base Conversion Number Base System Significant Figures Rounding Off Numbers Decimal Place Value Fraction Word Problems Word Problems in Fraction Multiplication and Division of Fractions Addition and Subtraction of Fractions Expressing One Quantity as a Percentage of Another Expressing One Quantity as a Fraction of Another


Academic Questions in Mathematics

Please click here to see all Questions and Answers

Decagon - Len Academy

What type of polygon is shown in the above image?

  • A. Nonagon

  • B. Decagon

  • C. Octagon

  • D. Hexagon

  • E. Hepagon

  • F. Pentagon

Which of the following is not part of a circle?

  • A. Section

  • B. Sector

  • C. Segment

  • D. Semicircle

  • E. Secant

  • F. Center

Acute Angle - Len Academy

What angle is shown in the above image?

  • A. Complementary

  • B. Supplementary

  • C. Acute

  • D. Obtuse

  • E. Reflex

  • F. Straight

An angle greater than 90o but less than 180o is termed _____.

  • A. Complementary

  • B. Supplementary

  • C. Acute

  • D. Obtuse

  • E. Reflex

  • F. Straight

Factorize 12a2 - 20a + 3

  • A. (6a - 1)(2a - 3)

  • B. (6a - 1)(2a + 3)

  • C. (6a + 1)(2a - 3)

  • D. (6a + 1)(2a + 3)

  • E. (-6a + 1)(2a - 3)

  • F. (-6a + 1)(2a + 3)

Simplify 10ab + 7ab

  • A. 17ab2

  • B. 17a2b2

  • C. 3ab2

  • D. 3a2b2

  • E. 17ab

  • F 3ab

Which of the following is not a type of angle?

  • A. Right angle

  • B. Left Angle

  • C. Acute Angle

  • D. Complete Angle

  • E. Straight Angle

  • F. Reflex angle

Two lines that can never meet each other are best considered as _____ lines.

  • A. straight
  • B. vertical
  • C. horizontal
  • D. parallel
  • E. oblique
  • F. perpendicular



Number Base Addition 


The addition of numbers in different bases is quite straightforward. It follows a similar procedure as in the addition of base 10. The principle of addition of number base is stated below:

In number base addition, when an addition in a column equals or exceeds the base number, we'll divide the sum by the base; writing down the remainder, and carrying the whole number quotient to the next column. 

This above principle is shown in binary or base 2 addition:

  • 0 + 0 = 0

  • 0 + 1 = 1

  • 1 + 1= 2/2 (Carry 1 and write down remainder 0)

  • 1 + 1 + 1 = 3/2 (Carry 1 and write down remainder 1)

Note: This same principle applies to other bases. That is: "when an addition in a column equals or exceeds the base number, we'll divide the sum by the base, while writing down the remainder, and carrying the whole number quotient to the next column". 

Please read on base 2 system (binary) here.

 

It is noteworthy to state that number base addition can easily be carried out through base 10 conversion. The steps below are followed using this method:

  • Step 1: Convert the bases to be added into base 10.

  • Step 2: Add the base 10 numbers (derived from step 1).

  • Step 3: Convert the base 10 addition result (in step 2) to the required base in the question.

Please read on number base conversion here.

You can read on the division of number bases here.

 


Worked Examples on Number Base Addition 


Example 1
  • 102 + 112

Solution 

Align the two binary numbers by their place values. This is shown below:

102
112
___
1012

 

Step 1: Add the rightmost digits.

0 + 1= 1

Step 2: Add the leftmost digits We add the leftmost digits:

1 + 1 = 2/2 (Carry 1 and write down remainder 0)

Step 3: 1 carried = 1

  • Answer: Combine the direct answers and remainder = 1012

 

Solution Through Base 10 Conversion

  • 102 + 112

Step 1: Convert 102 to base 10

(1 × 21) + (0 × 20)

2 + 0 = 210

Step 2: Convert 112 to base 10

(1 × 21) + (1 × 20)

2 + 1 = 310

Step 3: Add both base 10 results

2 + 3 = 510

Step 4: Covert the base 10 result to base 2

5 ÷ 2 = 2 R 1

2 ÷ 2 = 1 R 0

0 ÷ 2 = 0 R 1

Read remainder from bottom to top.

  • Answer: 1012

 

Example 2
  • 110112 + 11012

Solution 

Align the two base numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:

110112
011012
________
1010002

 

Step 1: Perform base addition with carries. Add the digits from right to left, following the base addition rule.

1 + 1 = 2/2 (Carry 1 and write down remainder 0)

Step 2: Second rightmost column

1 carried + 1 + 0 = 2/2 (Carry 1 and write down remainder 0)

Step 3: Third rightmost column

1 carried + 0 + 1 = 2/2 (Carry 1 and write down remainder 0)

Step 4: Fourth rightmost column

1 carried + 1 + 1 = 3/2 (Carry 1 and write down remainder 1)

Step 5: Left column

1 carried + 1 + 0 = 2/2 (Carry 1 and write down remainder 0)

Step 6: 1 + 0 = 1 

  • Answer: Combine the direct answers and remainders = 1010002

 

Solution Through Base 10 Conversion

  • 110112 + 11012

Step 1: Convert 110112 to base 10

(1 × 24) + (1 × 23) + (0 × 22) + (1 × 21) + (1 × 20)

16 + 8 + 0 + 2 + 1 = 2710

Step 2: Convert 11012 to base 10

(1 × 23) + (1 × 22) + (0 × 21) + (1 × 20)

8 + 4 + 0 + 1 = 1310

Step 3: Subtract both base 10 results

27 + 13 = 4010

Step 4: Covert the base 10 result to base 2

40 ÷ 2 = 20 R 0

20 ÷ 2 = 10 R 0

10 ÷ 2 = 5 R 0

5 ÷ 2 = 2 R 1

2 ÷ 2 = 1 R 0

1 ÷ 2 = 0 R 1

Read remainder from bottom to top.

  • Answer: 1010002

 

Example 3
  • 20334 + 300124

Solution 

Align the two base 4 numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:

020334
300124
________
321114

 

Step 1: Perform base 4 addition with carries. Add the digits from right to left, following the base addition rule.

3 + 2 = 5/4 (Carry 1 and write down remainder 1)

Step 2: Second rightmost column

1 carried + 3 + 1 = 5/4 (Carry 1 and write down remainder 1)

Step 3: Third rightmost column

1 carried + 0 + 0 = 1

Step 4: Fourth rightmost column

2 + 0 = 2

Step 5: Left column

0 + 3 = 3

  • Answer: Combine the direct answers and remainders = 321114

 

Solution Through Base 10 Conversion

  • 20334 - 300124

Step 1: Convert 20334 to base 10

(2 × 43) + (0 × 42) + (3 × 41) + (3 × 40)

128 + 0 + 12 + 3 = 14310

Step 2: Convert 300124 to base 10

(3 × 44) + (0 × 43) + (0 × 42) + (1 × 41) + (2 × 40)

768 + 0 + 0 + 4 + 2 = 77410

Step 3: Add both base 10 results

143 + 774 = 91710

Step 4: Covert the base 10 result to base 5

917 ÷ 4 = 229 R 1

229 ÷ 4 = 57 R 1

57 ÷ 4 = 14 R 1

14 ÷ 4 = 3 R 2

3 ÷ 4 = 0 R 3

Read remainder from bottom to top.

  • Answer: 321114

 

Example 4
  • 504426 + 3356

Solution 

Align the two base 6 numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:

504426
003356
________
512216

 

Step 1: Perform base 6 addition with carries. Add the digits from right to left, following the base addition rule.

5 + 2 = 7/6 (Carry 1 and write down remainder 1)

Step 2: Second rightmost column

1 carried + 4 + 3 = 8/6 (Carry 1 and write down remainder 2)

Step 3: Third rightmost column

1 carried + 4 + 3 = 8/6 (Carry 1 and write down remainder 2)

Step 4: Fourth rightmost column

1 carried + 0 + 0 = 1

Step 5: Left column

5 + 0 = 5

  • Answer: Combine the direct answers and remainders = 512216

 

Solution Through Base 10 Conversion

  • 504426 + 3356

Step 1: Convert 504426 to base 10

(5 × 64) + (0 × 63) + (4 × 62) + (4 × 61) + (2 × 60)

6480 + 0 + 144 + 24 + 2 = 665010

Step 2: Convert 3356 to base 10

(3 × 62) + (3 × 61) + (5 × 60)

108 + 18 + 5 = 13110

Step 3: Add both base 10 results

6650 + 131 = 678110

Step 4: Covert the base 10 result to base 5

6781 ÷ 6 = 1130 R 1

1130 ÷ 6 = 188 R 2

188 ÷ 6 = 31 R 2

31 ÷ 6 = 5 R 1

5 ÷ 6 = 0 R 5

Read remainder from bottom to top.

  • Answer: 512216

 

Example 5
  • 1012 + 1112

Solution 

Align the base numbers Align the two binary numbers by their place values.

1012
1112
________
11002

 

Step 1: Perform binary addition with carries. Add the digits from right to left, following base addition rules:

1 + 1 = 2/2 (Carry 1 and write down remainder 0)

Step 2: Second rightmost column

1 carried + 0 + 1 = 2/2 (Carry 1 and write down remainder 0)

Step 3: Left column

1 carried + 1 + 1 = 3/2 (Carry 1 and write down remainder 1)

Step 4: 1 carried = 1

Answer: Combine the direct answers and remainders = 11002

 

Solution Through Base 10 Conversion

  • 1012 + 1112

Step 1: Convert 430025 to base 10

(1 × 22) + (0 × 21) + (1 × 20)

4 + 0 + 1 = 510

Step 2: Convert 1112 to base 10

(1 × 22) + (1 × 21) + (1 × 20)

4 + 2 + 1 = 710

Step 3: Add both base 10 results

5 + 7 = 1210

Step 4: Covert the base 10 result to base 5

12 ÷ 2 = 6 R 0

6 ÷ 2 = 3 R 0

3 ÷ 2 = 1 R 1

1 ÷ 2 = 0 R 1

Read remainder from bottom to top.

  • Answer: 11002

 

Example 6
  • 104325 + 43215

Solution

Align the two base 5 numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:

104325
043215
________
203035

Step 1: Perform base 5 addition with carries. Add the digits from right to left, following the base addition rule.

2 + 1 = 3

Step 2: Second rightmost column

3 + 2 = 5/5 (Carry 1 and write down remainder 0)

Step 3: Third rightmost column

1 carried + 4 + 3 = 8/5 (Carry 1 and write down remainder 3)

Step 4: Fourth rightmost column

1 carried + 0 + 4 = 5/5 (Carry 1 and write down remainder 0)

Step 5: Left column

1 carried + 1 + 0 = 2 

  • Answer: Combine the direct answers and remainders = 203035

 

Solution Through Base 10 Conversion

  • 104325 + 43215

Step 1: Convert 104325 to base 10

(1 × 54) + (0 × 53) + (4 × 52) + (3 × 51) + (2 × 50)

625 + 0 + 100 + 15 + 2 = 74210

Step 2: Convert 43215 to base 10

(4 × 53) + (3 × 52) + (2 × 51) + (1 × 50)

500 + 75 + 10 + 1 = 58610

Step 3: Add both base 10 results

742 + 586 = 132810

Step 4: Covert the base 10 result to base 5

1328 ÷ 5 = 265 R 3

283 ÷ 5 = 53 R 0

53 ÷ 5 = 10 R 3

10 ÷ 5 = 2 R 0

2 ÷ 5 = 0 R 2

Read remainder from bottom to top.

  • Answer: 203035

 

Example 7
  • 222223 + 111113

Solution 

Align the two base 3 numbers by their place values. This is shown below:

222223
111113
_________
1111103

 

Step 1: Perform base 3 addition with carries. Add the digits from right to left, following the base addition rule.

2 + 1 = 3/3 (Carry 1 and write down remainder 0)

Step 2: Second rightmost column

1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)

Step 3: Third rightmost column

1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)

Step 4: Fourth rightmost column

1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)

Step 5: Left column

1 carried + 2 + 1 = 4/3 (Carry 1 and write down remainder 1)

Step 6: 1 carried = 1

  • Answer: Combine the direct answers and remainders = 1111103

 

Solution Through Base 10 Conversion

  • 222223 + 111113

Step 1: Convert 222223 to base 10

(2 × 34) + (2 × 33) + (2 × 32) + (2 × 31) + (2 × 30)

162 + 54 + 18 + 6 + 2 = 24210

Step 2: Convert 111113 to base 10

(1 × 34) + (1 × 33) + (1 × 32) + (1 × 31) + (1 × 30)

81 + 27 + 9 + 3 + 1 = 12110

Step 3: Add both base 10 results

242 + 121 = 36310

Step 4: Covert the base 10 result to base 5

363 ÷ 3 = 121 R 0

121 ÷ 3 = 40 R 1

40 ÷ 3 = 13 R 1

13 ÷ 3 = 4 R 1

4 ÷ 3 = 1 R 1

1 ÷ 3 = 0 R 1

Read remainder from bottom to top.

  • Answer: 1111103

 

Example 8
  • 11102 + 10012

Solution 

Align the two binary numbers by their place values. This is shown below:

11102
10012
________
101112

 

Step 1: Perform binary addition with carries. Add the digits from right to left, following the base addition rule:

0 + 1 = 1

Step 2: Second rightmost column

1 + 0 = 1

Step 3: Third rightmost column

1 + 0 = 1

Step 4: Left column

1 + 1 = 2/2 (Carry 1 and write down remainder 0) 

Step 5: 1 carried = 1

  • Answer: Combine the direct answers and remainders = 101112

 

Solution Through Base 10 Conversion

  • 11102 + 10012

Step 1: Convert 11102 to base 10

(1 × 23) + (1 × 22) + (1 × 21) + (0 × 20)

8 + 4 + 2 + 0 = 1410

Step 2: Convert 10012 to base 10

(1 × 23) + (0 × 22) + (0 × 21) + (1 × 20)

8 + 0 + 0 + 1 = 910

Step 3: Add both base 10 results

14 + 9 = 2310

Step 4: Covert the base 10 result to base 5

23 ÷ 2 = 11 R 1

11 ÷ 2 = 5 R 1

5 ÷ 2 = 2 R 1

2 ÷ 2 = 1 R 0

1 ÷ 2 = 0 R 1

Read remainder from bottom to top.

  • Answer: 101112

 

Example 9

1001002 + 112

Solution 

Align the two binary numbers by their place values. If possible, the shorter number can be padded with leading zeros for clarity. This is shown below:

1001002
0000112
________
1001112

 

Step 1: Perform binary addition with carries. Add the digits from right to left, following the base addition rules

0 + 1 = 1

Step 2: Second rightmost column

0 + 1 = 1

Step 3: Third rightmost column

1 + 0 = 1

Step 4: Fourth rightmost column

0 + 0 = 0

Step 5: Fifth rightmost column

0 + 0 = 0

Step 6: Left column

1 + 0 = 1

Answer: Combine the direct answers and remainders = 1001112

 

Solution Through Base 10 Conversion

  • 1001002 - 112

Step 1: Convert 1001002 to base 10

(1 × 25) + (0 × 24) + (0 × 23) + (1 × 22) + (0 × 21) + (0 × 20)

32 + 0 + 0 + 4 + 0 + 0 = 3610

Step 2: Convert 112 to base 10

(1 × 21) + (1 × 20)

2 + 1 = 310

Step 3: Add both base 10 results

36 + 3 = 3910

Step 4: Covert the base 10 result to base 5

39 ÷ 2 = 19 R 1

19 ÷ 2 = 9 R 1

9 ÷ 2 = 4 R 1

4 ÷ 2 = 2 R 0

2 ÷ 2 = 1 R 0

1 ÷ 2 = 0 R 1

Read remainder from bottom to top.

  • Answer: 1001112

Please read on subtraction of number bases here.

Please read on multiplication and division in algebra here.

Please read on the use of BODMAS in mathematics here.

 


Assignment on Addition of Number Bases


Add the following bases:

  • 3214 + 2134

  • 42315 + 12345

  • 38719 + 38879

  • 101101112 +.1101112

  • 7000018 +.1666678

  • 6543217 + 1234567

  • 432115 + 221435

  • 644437 + 163347

  • 78764910 + 9918110

  • 881239 + 235689

Please read on word problems leading to algebraic expressions here.

Please read on mathematics week 9 topic for jss1 first term here.

Please read on mathematics scheme of work for jss1 first term here.

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Amazing facts in Mathematics

The opposite sides of a dice will always give a sum of seven

31,556,926 seconds makes one year

From 0 through 1000, the only number that has the letter 'a' in it is 'one thousand'

÷

The division symbol '÷' is actually called an obelus

Four is the only number in the English language that is spelt with the same number of letters as the number (4) itself

40 is spelt as forty and not 'fourty'. It is the only number that is spelt with letters arranged in alphabetical order

An odd number is a number that cannot be divisible by 2.

Every odd number has an 'e' in its spelling. They include:

  • One
  • Three
  • Five
  • Seven
  • Nine

555 in Thailand sounds like 'hahaha'. This is because the number '5' means 'ha' in Thailand

In mathematics, 10! means 10 factorial. Below is its calculation:

10! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 3628800

Interestingly, 3628800 seconds is the same as 42 days

42 days is the same as 6 weeks

We can therefore say that 10! equals 6 weeks or 3628800 seconds in mathematics

When you multiply 111,111,111 by 111,111,111; the result equals 12,345,678,987,654,321


Notable points in Mathematics

Let's use algebra to explain the simple statement below:

I am a number. When you subtract 3 from me, the result is 9. what number am I ?

Of course we know the answer is 12. You probably guessed it from your mind because it was that simple. The truth is, We could have a much more complicated statement of such; and that is where algebra comes into play.

Now, to apply algebra in the above statement, we use letters or alphabets to represent the unknown number(s). So using algebra, we can write:

  • Let the number be y

  • y - 3 = 9

  • y = 9 + 3

  • y = 12

Please read more on algebra here

Sides of a right angle triangle - Len Academy

 

The image above shows a right angled triangle. The angle of the above right triangle is denoted as θ. Below are some points to note:

Hypotenuse is always the longest side of the triangle.

Opposite is the side opposite the angle (θ)

Adjacent is the shorter side next to the angle (θ)

Each of Sin θ, cos θ and tan θ are the ratio of sides of the right triangle. They are calculated by using the formula (margic word) sohcahtoa:

Sohcahtoa - Len Academy

soh

Sin θ = Opposite/Hypotenuse

cah

Cos θ = Adjacent/Hypotenuse

toa

Tan θ = Opposite/Adjacent

Please read more on sine, cosine and tangent here

Circumference of a Circle - Len Academy

Circumference in mathematics means the distance around the edge of a circle (or a another curved surface).

Circumference is to circle or any other curved surface

Perimeter of a Rectangle - Len Academy

Perimeter means the distance around a square or rectangle or polygon.

Perimeter is to square or rectangle or polygon